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JEE Main 2013Medium

Q.A rod has λ=kx2.λ = k x^2. The potential at end is

a
kL3/(12×4πϵ0)k L^3 / (12 \times 4\pi \epsilon_0)
b
kL2/(4πϵ0)k L^2 / (4 \pi \epsilon_0)
c
kL/(4πϵ0)k L / (4 \pi \epsilon_0)
d
none

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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