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JEE Main 2012Medium

Q.A ring has λ = λ₀ cos 2θ. The electric field at centre is

a
zero
b
λ0πϵ0R\dfrac{\lambda_0}{ \pi \epsilon_0 R}
c
2λ0πϵ0R\dfrac{2 \lambda_0}{ \pi \epsilon_0 R}
d
λ02πϵ0R\dfrac{\lambda_0}{2 \pi \epsilon_0 R}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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