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Q.A thin rod of length L has linear charge density λ = λ₀ (L - x)/L. The electric field at a point on the perpendicular bisector at distance d from centre is

a
λ04πϵ0d\dfrac{\lambda_0}{4\pi \epsilon_0 d}
b
λ02πϵ0d\dfrac{\lambda_0}{2\pi \epsilon_0 d}
c
λ0L4πϵ0d2\dfrac{\lambda_0 L}{4\pi \epsilon_0 d^2}
d
λ0πϵ0d\dfrac{\lambda_0}{ \pi \epsilon_0 d}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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