Q.A disc of radius R has surface charge density σ = σ₀ r. The electric field on the axis at distance x from centre is

\dfrac{\sigma_0 R^2}{4 \epsilon_0} \left( \dfrac{1}{x} - \dfrac{1}{\sqrt{x^2 + R^2}} \right)

\dfrac{\sigma_0}{2 \epsilon_0} \left( 1 - \dfrac{x}{\sqrt{x^2 + R^2}} \right)

\dfrac{\sigma_0 R}{2 \epsilon_0 x}

\dfrac{\sigma_0 R^2}{2 \epsilon_0 (x^2 + R^2)}

The correct solution involves applying the fundamental concept to derive the final value step by step...

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