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JEE Main 2023Medium

Q.A rod of length L has λ = λ₀ sin(πx/L). The electric field at the midpoint perpendicular to rod at distance d is

a
zero
b
λ02πϵ0d\dfrac{\lambda_0}{2 \pi \epsilon_0 d}
c
λ0πϵ0d\dfrac{\lambda_0}{ \pi \epsilon_0 d}
d
λ0L4πϵ0d\dfrac{\lambda_0 L}{4 \pi \epsilon_0 d}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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