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Q.A quarter arc has λ = λ₀ sinθ. The electric field at centre is

a
λ0(2−1)πϵ0R\dfrac{\lambda_0 (\sqrt{2} - 1)}{ \pi \epsilon_0 R}
b
λ0πϵ0R\dfrac{\lambda_0}{ \pi \epsilon_0 R}
c
zero
d
λ02πϵ0R\dfrac{\lambda_0 \sqrt{2}}{ \pi \epsilon_0 R}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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