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Q.A disc has σ=σ0(r2/R2)σ = σ₀ (r^2 / R^2). The potential at centre is

a
σ0R2/(6ϵ0)\sigma_0 R^2 / (6 \epsilon_0)
b
zero
c
σ0R/(2ϵ0)\sigma_0 R / (2 \epsilon_0)
d
σ0R2/(3ϵ0)\sigma_0 R^2 / (3 \epsilon_0)

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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