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JEE Main 2012Medium

Q.A disc has σ = σ₀ sin 2θ. The electric field at centre is

a
zero
b
σ0/(πϵ0)\sigma_0 / ( \pi \epsilon_0)
c
σ0/(2πϵ0)\sigma_0 / (2 \pi \epsilon_0)
d
σ0/(4πϵ0)\sigma_0 / (4 \pi \epsilon_0)

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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