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JEE Main 2008Medium

Q.A disc of radius R has σ = σ₀ sinθ. The electric field at centre is

a
σ0πϵ0\dfrac{\sigma_0}{ \pi \epsilon_0}
b
zero
c
σ02πϵ0\dfrac{\sigma_0}{2 \pi \epsilon_0}
d
σ04πϵ0\dfrac{\sigma_0}{4 \pi \epsilon_0}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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