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Q.The magnetic field at the centre of a current-carrying equilateral triangular loop of side a is

a
μ0I32πa\dfrac{\mu_0 I \sqrt{3}}{2\pi a}
b
3μ0I2πa\dfrac{3\mu_0 I}{2\pi a}
c
9μ0I2πa\dfrac{9\mu_0 I}{2\pi a}
d
6μ0Iπa\dfrac{6\mu_0 I}{\pi a}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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