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Q.The force acting on a charge 2 µC moving with velocity 5 m/s in a field 0.2 T at 30° to the field is

a
10610^{-6} N
b
2×1062 \times 10^{-6} N
c
4×1064 \times 10^{-6} N
d
8×1068 \times 10^{-6} N

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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The force acting on a charge 2 µC moving with velocity 5 m/s... | ParikshaNiti