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Q.जर x:y:z=2:3:5x:y:z=2:3:5 आणि x+y+z=200x+y+z=200 असेल तर xy+yz+zxxy+yz+zx किती?

a
86008600
b
88008800
c
90009000
d
92009200

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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