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Q.A particle of charge 2e-2e and mass 4m4m enters a magnetic field with velocity vv perpendicular to B. Compared to a proton moving with same vv, its radius is

a
same
b
twice
c
half
d
four times

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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A particle of charge -2e and mass 4m enters a magnetic f... | ParikshaNiti