Q.The horizontal component of Earth’s field is $3.6 \times 10^{-5}\,\text{T}$ and total field is $6 \times 10^{-5}\,\text{T}$ . The dip angle is

30°

53°

60°

37°

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The horizontal component of Earth’s field is 3.6×10−5 T3.6 \times 10^{-5}\,\text{T}3.6×10−5T and total field is 6×10−5 T6 \times 10^{-5}\,\text{T}6×10−5T. The dip angle is