Home/Question #597
PracticeMedium

Q.The magnetic field at the centre of a current-carrying arc of 60° is

a
μ0I6R\dfrac{\mu_0 I}{6R}
b
μ0I12R\dfrac{\mu_0 I}{12R}
c
μ0Iπ6R\dfrac{\mu_0 I \pi}{6R}
d
μ0I3R\dfrac{\mu_0 I}{3R}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here