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Q.The de-Broglie wavelength of an electron accelerated through potential VV is λ\lambda. If accelerated through 4V4V, the wavelength becomes

a
λ\lambda
b
2λ2\lambda
c
λ/2\lambda/2
d
λ/4\lambda/4

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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