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Q.A compound with molar mass 159 g/mol159 \text{ g/mol} has C,HC, H and NN in 9:1:3.59:1:3.5 ratio by mass. The molecular formula is:

a
C_6H_8N_2
b
C_9H_{12}N_3
c
C_5H_7N
d
C_{12}H_{16}N_4

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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