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Q.A 2 m long wire of resistance 4 Ω and diameter 0.64 mm is coated with plastic insulation of thickness 0.08 mm. When a 6 V battery is connected, the current is 0.5 A. The resistivity of the wire material is

a
10−6Ω10^{-6} \Omegam
b
2×10−6Ω2 \times 10^{-6} \Omegam
c
4×10−6Ω4 \times 10^{-6} \Omegam
d
8×10−6Ω8 \times 10^{-6} \Omegam

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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