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Q.The uncertainty in momentum of an electron is 1×105 kg m s11 \times 10^{-5} \text{ kg m s}^{-1}. The uncertainty in its position is: (h=6.62×1034 J sh = 6.62 \times 10^{-34} \text{ J s})

a
5.27×1030 m5.27 \times 10^{-30} \text{ m}
b
1.05×1029 m1.05 \times 10^{-29} \text{ m}
c
5.27×1028 m5.27 \times 10^{-28} \text{ m}
d
1.05×1030 m1.05 \times 10^{-30} \text{ m}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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