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Q.If n=6n=6, the correct sequence of filling of electrons will be:

a
ns→(n−2)f→(n−1)d→npns \rightarrow (n-2)f \rightarrow (n-1)d \rightarrow np
b
ns→(n−1)d→(n−2)f→npns \rightarrow (n-1)d \rightarrow (n-2)f \rightarrow np
c
ns→np→(n−1)d→(n−2)fns \rightarrow np \rightarrow (n-1)d \rightarrow (n-2)f
d
None of these

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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