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Q.The de-Broglie wavelength of a neutron at 27°C is λ. At 927°C, its wavelength will be

a
λ/2\lambda/2
b
λ/4\lambda/4
c
λ/2\lambda/\sqrt{2}
d
λ2\lambda \sqrt{2}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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