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NEET 2024Easy

Q.In the reaction Cr2O72+14H++6e2Cr3++7H2OCr_2O_7^{2-} + 14H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O, the oxidizing agent is:

a
Cr2O72Cr_2O_7^{2-}
b
H+H^+
c
Cr3+Cr^{3+}
d
H2OH_2O

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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