Home/Question #6551
COMMON (JEE/NEET)Easy

Q.The vapor pressure of a solvent is P∘P^{\circ}. When a non-volatile solute is added, the vapor pressure becomes PP. The relative lowering of vapor pressure is given by:

a
P∘−PP^{\circ} - P
b
(P∘−P)/P∘(P^{\circ} - P) / P^{\circ}
c
(P∘−P)/P(P^{\circ} - P) / P
d
P/P∘P / P^{\circ}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here