Home/Question #6570
JEE MainHard

Q.The boiling point of a solution of 0.1050 g0.1050 \text{ g} of a substance in 15.84 g15.84 \text{ g} of ether was found to be 0.1C0.1^{\circ}C higher than that of pure ether. What is the molecular weight of the substance? (Kb for ether=2.16 K kg mol1K_b \text{ for ether} = 2.16 \text{ K kg mol}^{-1})

a
143.5 g/mol143.5 \text{ g/mol}
b
160.2 g/mol160.2 \text{ g/mol}
c
135.4 g/mol135.4 \text{ g/mol}
d
150.0 g/mol150.0 \text{ g/mol}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here