Q.The rate law for a reaction is Rate $= k[A]^2 [B]$ . If the concentration of $B$ is doubled and $A$ is halved, the new rate will be:

Half the original rate

Double the original rate

Same as the original rate

One-fourth the original rate

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The rate law for a reaction is Rate =k[A]2[B]= k[A]^2 [B]=k[A]2[B]. If the concentration of BBB is doubled and AAA is halved, the new rate will be: