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COMMON (JEE/NEET)Easy

Q.The relationship between ΔG\Delta G and QQ is given by:

a
ΔG=ΔG∘+RTln⁡Q\Delta G = \Delta G^{\circ} + RT \ln Q
b
ΔG=ΔG∘−RTln⁡Q\Delta G = \Delta G^{\circ} - RT \ln Q
c
ΔG∘=RTln⁡Q\Delta G^{\circ} = RT \ln Q
d
ΔG=RTln⁡(Q/K)\Delta G = RT \ln (Q/K)

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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