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NEET 2024Medium

Q.The solubility product (KspK_{sp}) of Ag2CrO4Ag_2CrO_4 is 1.1×10−121.1 \times 10^{-12}. Its solubility (ss) in moles per liter is given by:

a
s=(Ksp)1/2s = (K_{sp})^{1/2}
b
s=(Ksp/4)1/3s = (K_{sp}/4)^{1/3}
c
s=(Ksp/27)1/4s = (K_{sp}/27)^{1/4}
d
s=Ksp/2s = K_{sp}/2

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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