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Q.The solubility of CaF2CaF_2 in a solution of 0.1 M NaF0.1 \text{ M } NaF is (KspK_{sp} of CaF2=4×10−11CaF_2 = 4 \times 10^{-11}):

a
4×10−9 M4 \times 10^{-9} \text{ M}
b
2×10−5 M2 \times 10^{-5} \text{ M}
c
4×10−10 M4 \times 10^{-10} \text{ M}
d
4×10−8 M4 \times 10^{-8} \text{ M}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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