Home/Question #6866

JEE MainHard

Q.The solubility product of $CuS$ , $Ag_2S$ , and $HgS$ are $10^{-31}, 10^{-44}$ , and $10^{-54}$ respectively. The order of their solubility in water is:

a

HgS > Ag_2S > CuS

b

CuS > Ag_2S > HgS

c

Ag_2S > CuS > HgS

d

Ag_2S > HgS > CuS

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here