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COMMON (JEE/NEET)Easy

Q.The solubility of A2BA_2B is 2×10−4 mol L−12 \times 10^{-4} \text{ mol L}^{-1}. Its solubility product is:

a
3.2×10−113.2 \times 10^{-11}
b
4×10−84 \times 10^{-8}
c
8×10−128 \times 10^{-12}
d
1.6×10−111.6 \times 10^{-11}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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