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NEET 2024Easy

Q.If the solubility product of Cd(OH)2Cd(OH)_2 is 2×10−142 \times 10^{-14}, its solubility in a solution with [OH−]=0.01 M[OH^-] = 0.01 \text{ M} is:

a
2×10−10 M2 \times 10^{-10} \text{ M}
b
2×10−12 M2 \times 10^{-12} \text{ M}
c
1×10−10 M1 \times 10^{-10} \text{ M}
d
4×10−10 M4 \times 10^{-10} \text{ M}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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