Q.The work done during the expansion of a gas from $4 \text{ L}$ to $6 \text{ L}$ against a constant external pressure of $3 \text{ atm}$ is: ( $1 \text{ L atm} = 101.32 \text{ J}$ )

-607.92 \text{ J}

-303.96 \text{ J}

-6 \text{ J}

+607.92 \text{ J}

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Q.The work done during the expansion of a gas from 4 L4 \text{ L}4 L to 6 L6 \text{ L}6 L against a constant external pressure of 3 atm3 \text{ atm}3 atm is: (1 L atm=101.32 J1 \text{ L atm} = 101.32 \text{ J}1 L atm=101.32 J)