Q.The molar conductivity of a $0.001 \text{ M}$ acetic acid solution is $50 \text{ S cm}^2 \text{ mol}^{-1}$ . If the limiting molar conductivity is $400 \text{ S cm}^2 \text{ mol}^{-1}$ , the degree of dissociation ( $\alpha$ ) is:

0.125

0.0125

0.5

0.1

The correct solution involves applying the fundamental concept to derive the final value step by step...

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