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COMMON (JEE/NEET)Easy

Q.In a simple cubic lattice, the edge length 'aa' is related to the radius of the atom 'rr' as:

a
a=ra = r
b
a=2ra = 2r
c
a=22ra = 2\sqrt{2}r
d
a=3r/4a = \sqrt{3}r / 4

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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