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COMMON (JEE/NEET)Medium

Q.Bragg's law is given by the equation:

a
nλ=2dsinθn\lambda = 2d \sin \theta
b
nλ=dsinθn\lambda = d \sin \theta
c
nλ=2dcosθn\lambda = 2d \cos \theta
d
λ=2dsinθ\lambda = 2d \sin \theta

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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