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COMMON (JEE/NEET)Easy

Q.The general electronic configuration of Lanthanoids is:

a
[Xe]4f1−145d0−16s2[Xe] 4f^{1-14} 5d^{0-1} 6s^2
b
[Xe]4f0−145d1−106s2[Xe] 4f^{0-14} 5d^{1-10} 6s^2
c
[Rn]5f1−146d0−17s2[Rn] 5f^{1-14} 6d^{0-1} 7s^2
d
[Xe]4f75d16s2[Xe] 4f^7 5d^1 6s^2

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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