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Q.The optical rotation of a mixture containing 60%60\% of (+)(+) enantiomer and 40%40\% of ()(-) enantiomer will be:

a
20%20\% of the rotation of pure (+)(+) enantiomer
b
100%100\% of the rotation of pure (+)(+) enantiomer
c
0%0\% (Racemic mixture)
d
20%20\% of the rotation of pure ()(-) enantiomer

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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