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Q.The de-Broglie wavelength of a proton and an electron accelerated through same potential are λp\lambda_p and λe\lambda_e. Then λe/λp\lambda_e/\lambda_p is

a
1836\sqrt{1836}
b
1836
c
1/18361/\sqrt{1836}
d
1836/2\sqrt{1836}/2

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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