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COMMON (JEE/NEET)Easy

Q.Acetamide is treated with Br2Br_2 and KOHKOH to give methylamine. If we start with CH3CH2CONH2CH_3CH_2CONH_2, the product will be:

a
Ethylamine
b
Propylamine
c
Methylamine
d
Butylamine

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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