Q.In the estimation of phosphorus, $0.40$ g of an organic compound gave $1.1$ g of magnesium pyrophosphate ( $Mg_2P_2O_7$ ). The percentage of phosphorus is: [Molar mass: $Mg_2P_2O_7 = 222$ , $P = 31$ ]

76.8%

31.0%

15.5%

45.2%

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Q.In the estimation of phosphorus, 0.400.400.40 g of an organic compound gave 1.11.11.1 g of magnesium pyrophosphate (Mg2P2O7Mg_2P_2O_7Mg2​P2​O7​). The percentage of phosphorus is: [Molar mass: Mg2P2O7=222Mg_2P_2O_7 = 222Mg2​P2​O7​=222, P=31P = 31P=31]